Integrand size = 20, antiderivative size = 112 \[ \int \frac {\sqrt {a+b x^3+c x^6}}{x^4} \, dx=-\frac {\sqrt {a+b x^3+c x^6}}{3 x^3}-\frac {b \text {arctanh}\left (\frac {2 a+b x^3}{2 \sqrt {a} \sqrt {a+b x^3+c x^6}}\right )}{6 \sqrt {a}}+\frac {1}{3} \sqrt {c} \text {arctanh}\left (\frac {b+2 c x^3}{2 \sqrt {c} \sqrt {a+b x^3+c x^6}}\right ) \]
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Time = 0.07 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {1371, 746, 857, 635, 212, 738} \[ \int \frac {\sqrt {a+b x^3+c x^6}}{x^4} \, dx=-\frac {b \text {arctanh}\left (\frac {2 a+b x^3}{2 \sqrt {a} \sqrt {a+b x^3+c x^6}}\right )}{6 \sqrt {a}}+\frac {1}{3} \sqrt {c} \text {arctanh}\left (\frac {b+2 c x^3}{2 \sqrt {c} \sqrt {a+b x^3+c x^6}}\right )-\frac {\sqrt {a+b x^3+c x^6}}{3 x^3} \]
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Rule 212
Rule 635
Rule 738
Rule 746
Rule 857
Rule 1371
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {\sqrt {a+b x+c x^2}}{x^2} \, dx,x,x^3\right ) \\ & = -\frac {\sqrt {a+b x^3+c x^6}}{3 x^3}+\frac {1}{6} \text {Subst}\left (\int \frac {b+2 c x}{x \sqrt {a+b x+c x^2}} \, dx,x,x^3\right ) \\ & = -\frac {\sqrt {a+b x^3+c x^6}}{3 x^3}+\frac {1}{6} b \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x+c x^2}} \, dx,x,x^3\right )+\frac {1}{3} c \text {Subst}\left (\int \frac {1}{\sqrt {a+b x+c x^2}} \, dx,x,x^3\right ) \\ & = -\frac {\sqrt {a+b x^3+c x^6}}{3 x^3}-\frac {1}{3} b \text {Subst}\left (\int \frac {1}{4 a-x^2} \, dx,x,\frac {2 a+b x^3}{\sqrt {a+b x^3+c x^6}}\right )+\frac {1}{3} (2 c) \text {Subst}\left (\int \frac {1}{4 c-x^2} \, dx,x,\frac {b+2 c x^3}{\sqrt {a+b x^3+c x^6}}\right ) \\ & = -\frac {\sqrt {a+b x^3+c x^6}}{3 x^3}-\frac {b \tanh ^{-1}\left (\frac {2 a+b x^3}{2 \sqrt {a} \sqrt {a+b x^3+c x^6}}\right )}{6 \sqrt {a}}+\frac {1}{3} \sqrt {c} \tanh ^{-1}\left (\frac {b+2 c x^3}{2 \sqrt {c} \sqrt {a+b x^3+c x^6}}\right ) \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.96 \[ \int \frac {\sqrt {a+b x^3+c x^6}}{x^4} \, dx=\frac {1}{3} \left (-\frac {\sqrt {a+b x^3+c x^6}}{x^3}+\frac {b \text {arctanh}\left (\frac {\sqrt {c} x^3-\sqrt {a+b x^3+c x^6}}{\sqrt {a}}\right )}{\sqrt {a}}-\sqrt {c} \log \left (b+2 c x^3-2 \sqrt {c} \sqrt {a+b x^3+c x^6}\right )\right ) \]
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\[\int \frac {\sqrt {c \,x^{6}+b \,x^{3}+a}}{x^{4}}d x\]
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none
Time = 0.28 (sec) , antiderivative size = 601, normalized size of antiderivative = 5.37 \[ \int \frac {\sqrt {a+b x^3+c x^6}}{x^4} \, dx=\left [\frac {2 \, a \sqrt {c} x^{3} \log \left (-8 \, c^{2} x^{6} - 8 \, b c x^{3} - b^{2} - 4 \, \sqrt {c x^{6} + b x^{3} + a} {\left (2 \, c x^{3} + b\right )} \sqrt {c} - 4 \, a c\right ) + \sqrt {a} b x^{3} \log \left (-\frac {{\left (b^{2} + 4 \, a c\right )} x^{6} + 8 \, a b x^{3} - 4 \, \sqrt {c x^{6} + b x^{3} + a} {\left (b x^{3} + 2 \, a\right )} \sqrt {a} + 8 \, a^{2}}{x^{6}}\right ) - 4 \, \sqrt {c x^{6} + b x^{3} + a} a}{12 \, a x^{3}}, -\frac {4 \, a \sqrt {-c} x^{3} \arctan \left (\frac {\sqrt {c x^{6} + b x^{3} + a} {\left (2 \, c x^{3} + b\right )} \sqrt {-c}}{2 \, {\left (c^{2} x^{6} + b c x^{3} + a c\right )}}\right ) - \sqrt {a} b x^{3} \log \left (-\frac {{\left (b^{2} + 4 \, a c\right )} x^{6} + 8 \, a b x^{3} - 4 \, \sqrt {c x^{6} + b x^{3} + a} {\left (b x^{3} + 2 \, a\right )} \sqrt {a} + 8 \, a^{2}}{x^{6}}\right ) + 4 \, \sqrt {c x^{6} + b x^{3} + a} a}{12 \, a x^{3}}, \frac {\sqrt {-a} b x^{3} \arctan \left (\frac {\sqrt {c x^{6} + b x^{3} + a} {\left (b x^{3} + 2 \, a\right )} \sqrt {-a}}{2 \, {\left (a c x^{6} + a b x^{3} + a^{2}\right )}}\right ) + a \sqrt {c} x^{3} \log \left (-8 \, c^{2} x^{6} - 8 \, b c x^{3} - b^{2} - 4 \, \sqrt {c x^{6} + b x^{3} + a} {\left (2 \, c x^{3} + b\right )} \sqrt {c} - 4 \, a c\right ) - 2 \, \sqrt {c x^{6} + b x^{3} + a} a}{6 \, a x^{3}}, \frac {\sqrt {-a} b x^{3} \arctan \left (\frac {\sqrt {c x^{6} + b x^{3} + a} {\left (b x^{3} + 2 \, a\right )} \sqrt {-a}}{2 \, {\left (a c x^{6} + a b x^{3} + a^{2}\right )}}\right ) - 2 \, a \sqrt {-c} x^{3} \arctan \left (\frac {\sqrt {c x^{6} + b x^{3} + a} {\left (2 \, c x^{3} + b\right )} \sqrt {-c}}{2 \, {\left (c^{2} x^{6} + b c x^{3} + a c\right )}}\right ) - 2 \, \sqrt {c x^{6} + b x^{3} + a} a}{6 \, a x^{3}}\right ] \]
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\[ \int \frac {\sqrt {a+b x^3+c x^6}}{x^4} \, dx=\int \frac {\sqrt {a + b x^{3} + c x^{6}}}{x^{4}}\, dx \]
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Exception generated. \[ \int \frac {\sqrt {a+b x^3+c x^6}}{x^4} \, dx=\text {Exception raised: ValueError} \]
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\[ \int \frac {\sqrt {a+b x^3+c x^6}}{x^4} \, dx=\int { \frac {\sqrt {c x^{6} + b x^{3} + a}}{x^{4}} \,d x } \]
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Time = 8.57 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.81 \[ \int \frac {\sqrt {a+b x^3+c x^6}}{x^4} \, dx=\frac {\sqrt {c}\,\ln \left (\sqrt {c\,x^6+b\,x^3+a}+\frac {c\,x^3+\frac {b}{2}}{\sqrt {c}}\right )}{3}-\frac {\sqrt {c\,x^6+b\,x^3+a}}{3\,x^3}-\frac {b\,\ln \left (\frac {b}{2}+\frac {a}{x^3}+\frac {\sqrt {a}\,\sqrt {c\,x^6+b\,x^3+a}}{x^3}\right )}{6\,\sqrt {a}} \]
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